2X^2+33x+100=0

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Solution for 2X^2+33x+100=0 equation: 



2X^2+33X+100=0

a = 2; b = 33; c = +100;
Δ = b2-4ac
Δ = 332-4·2·100
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-17}{2*2}=\frac{-50}{4}
=-12+1/2
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+17}{2*2}=\frac{-16}{4}
=-4
$

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